2.5^(2x)/4^x=5

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Solution for 2.5^(2x)/4^x=5 equation: 



2.5^(2x)/4^x=5

We move all terms to the left:

2.5^(2x)/4^x-(5)=0



Domain of the equation: 4^x!=0

x!=0/1

x!=0

x∈R



We multiply all the terms by the denominator


2.5^2x-5*4^x=0

Wy multiply elements

2.5^2x-20x=0

We add all the numbers together, and all the variables

-20x+2.5^2x=0

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